solve the integral $\int_{0}^{‡}\frac{x^2dx}{({1-x^2})^2}$
Solve the following integral:
$$\int_{0}^{‡}\frac{x^2dx}{({1-x^2})^2}$$
One of my friends asked me this question and I was not able to find the
result. I tried replacing x by $\tan\theta$ and I think $\sin\theta$ can't
be used as the limits are from 0 to ‡
Anyone please give me hints to solve this
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